Question

What is the standard cell notation of a galvanic cell made with magnesium (mg) and gold (au)? a. au(s) | au (aq) || mg2 (aq) | mg(s) b. mg(s) | mg2 (aq) || au (aq) | au(s) c. mg2 (aq) | mg(s) || au(s) | au (aq) d. au (aq) | au(s) || mg(s) | mg2 (aq)

Answer 1

The standard cell notation of a galvanic cell made with magnesium (Mg) and gold (Au) is d. au (aq) | au(s) || mg(s) | mg2 (aq).

Step-by-step explanation:

The standard cell notation of a galvanic cell made with magnesium (Mg) and gold (Au) is d. au (aq) | au(s) || mg(s) | mg2 (aq).

The anode, where oxidation occurs, is represented on the left side of the notation. In this case, gold (Au) is being oxidized and is written as Au(s) on the left side.

The cathode, where reduction occurs, is represented on the right side of the notation. In this case, magnesium (Mg) is being reduced and is written as Mg(s) on the right side.

The two vertical lines represent a salt bridge or a porous barrier that allows the movement of ions between the two half-cells.

Answer 2

The standard cell notation for a galvanic cell made with magnesium and gold is 'd. au (aq) | au(s) || mg(s) | mg2 (aq)'.

Step-by-step explanation:

The correct standard cell notation for a galvanic cell made with magnesium (Mg) and gold (Au) is d. au (aq) | au(s) || mg(s) | mg2 (aq).

In the standard cell notation, the anode (oxidation half-cell) is always written on the left, and the cathode (reduction half-cell) is always written on the right. The ions in the solution are represented by their respective electrolyte solutions, followed by the electrode material in its solid state.

In this case, the oxidation half-cell involves the conversion of solid magnesium (Mg) to Mg2+ ions, while the reduction half-cell involves the deposition of gold (Au) ions as solid gold on the electrode.