Final answer:
Graph B shows the inequality that represents this situation with the solution region shaded. Yes, Rochelle will be able to cover her weekly expenses if she works for 5 hours and makes 15 bracelets, because the point (5,15) lies in the solution region.
Explanation:
Graph B has a solid boundary line that intersects the x-axis at 40 and the y-axis at 20. This means that if Rochelle works for 40 hours at the museum, she will earn $400 (40 x $10) and if she sells 20 bracelets, she will earn $100 (20 x $5), making her total weekly income $500. However, since she only needs to earn $200 to cover her expenses, the solution region is shaded to show all the possible combinations of hours worked and bracelets sold that would result in an income of at least $200.
Now, if we plug in the values of x = 5 and y = 15 into the inequality, we get 5(10) + 15(5) ≥ 200, which simplifies to 50 + 75 ≥ 200, or 125 ≥ 200. This means that Rochelle's income from working for 5 hours and selling 15 bracelets is $125, which is more than enough to cover her expenses.
In other words, Rochelle's weekly income can be represented by the equation 10x + 5y ≥ 200, where x is the number of hours worked and y is the number of bracelets sold. The solution region shaded on graph B shows all the possible solutions that would satisfy this inequality and result in an income of at least $200.
Therefore, graph B is the correct answer as it accurately represents the given situation with its solution region shaded. Rochelle will be able to cover her expenses if she works for 5 hours and makes 15 bracelets, as this point lies in the shaded region indicating a solution to the inequality. This also means that there are other combinations of hours worked and bracelets sold within the shaded region that would result in an income of at least $200, giving Rochelle some flexibility in terms of how she can meet her financial needs.