Question

If 28.0 grams of pb(no3)2 react with 18.0 grams of nai, what mass of pbi2 can be produced? pb(no3)2 nai → pbi2 nano3 (3 points) 27.7 g pbi2 39.0 g pbi2 44.8 g pbi2 56.1 g pbi2

Answer 1

To find the mass of PbI2 produced, use the concept of limiting reactants. The mass of PbI2 produced is 27.7 g.

Step-by-step explanation:

The given balanced chemical equation is:

Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3

To find the mass of PbI2 produced, we need to use the concept of limiting reactants. First, we calculate the number of moles of each reactant:

Moles of Pb(NO3)2 = 28.0g / molar mass of Pb(NO3)2

Moles of NaI = 18.0g / molar mass of NaI

The limiting reactant is the one that produces the least amount of product. Compare the moles of Pb(NO3)2 and NaI to determine which is limiting.

Next, calculate the moles of PbI2 produced using the stoichiometric ratio from the balanced equation:

Moles of PbI2 = Moles of limiting reactant x stoichiometric ratio

Finally, calculate the mass of PbI2 produced:

Mass of PbI2 = Moles of PbI2 x molar mass of PbI2

Therefore, the mass of PbI2 produced is 27.7 g.