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A 100.0 g sample of titanium at 63.0 °c is warmed to 85.0 °c. how much energy is needed to warm the metal? (ct. = 0.130 , 12) q = [?]j

User Limo
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Final answer:

The energy needed to warm a 100.0g sample of titanium from 63.0 °c to 85.0 °c is calculated using the formula Q = mcΔT. Substituting the given values, we find that 286 J of energy is needed.

Step-by-step explanation:

The energy needed to change the temperature of a substance is determined by the formula Q = mcΔT, where Q is the heat energy, m is the mass of the substance, ΔT is the temperature change, and c is the specific heat capacity of the substance. In this case, we can substitute the given values into the formula:

Q = (100.0g) * (0.130 J/g°C) * (85.0°C - 63.0°C)

Calculate the difference in temperature (ΔT = 85.0°C - 63.0°C = 22.0°C), then multiply the other values:

Q = 100.0 g * 0.130 J/g°C * 22.0°C = 286 J

So, to warm a 100.0g sample of titanium from 63.0 °c to 85.0 °c, requires 286 J of energy.

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User Sean Adkinson
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