Question

Using point slope form, find the equation of a line that has a slope of 2, and passes through the point (-1,-3).

Answer 1

`\bf{y+3=2(x+1)}`

Explanation:

In order to find the equation, I am going to use the point-slope form:

`\bf{y-y_1=m(x-x_1)}`

where:

m = slope

`\bf{(x_1,y_1)}` is a point on the line

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Put in the values:

`\bf{y-(-3)=2(x-(-1)}`

`\bf{y+3=2(x+1)}`

Therefore, this is our point-slope equation.

Answer 2

y + 3 = 2(x + 1)

Explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

given slope m = 2 and (a, b ) = (- 1, - 3 ) , then

y - (- 3) = 2(x - (- 1) ) , that is

y + 3 = 2(x + 1) ← in point- slope form