Question

A 8.25 L container holds a mixture of two gases at 21∘C. The partial pressures of gas A and gas B, respectively, are 0.323 atm and 0.660 atm. If 0.130 mol of a third gas is added with no change in volume or temperature, what will the total pressure become? Ptota atm

Answer 1

To determine the total pressure in the container after adding a third gas, we calculate its pressure using the ideal gas law and add it to the existing partial pressures of gas A and gas B, applying Dalton's law of partial pressures.

Step-by-step explanation:

The student's question is about calculating the total pressure in a container holding a mixture of gases using Dalton's law of partial pressures. To find the total pressure after adding a third gas to the container with partial pressures of gas A and gas B being 0.323 atm and 0.660 atm, we add the partial pressures of the gases together, including the pressure contributed by the third gas.

First, we need to calculate the pressure of the third gas using the ideal gas law (PV=nRT), with the provided conditions and the universal gas constant. Once we have the pressure of the third gas, we can use Dalton's law to find the total pressure by adding it to the sum of the other two partial pressures.

Answer 2

By applying Dalton's law of partial pressures, the total pressure after adding a third gas to a mixture of two gases in a container is found by summing the individual partial pressures. After calculating the partial pressure of the third gas using the ideal gas law, the total pressure in the container is approximately 1.372 atm.

Step-by-step explanation:

To find the total pressure in the container after adding a third gas, we can apply Dalton's law of partial pressures which states that the total pressure of a mixture of gases is equal to the sum of their individual partial pressures.

Initially, we have the partial pressures of gas A and gas B, which are 0.323 atm and 0.660 atm, respectively. The pressure of the third gas can be found using the ideal gas law:

PV = nRT

For the third gas, at a fixed volume (8.25 L) and temperature (21°C), and with a known amount (0.130 mol), we can calculate its partial pressure.

However, we need the value of R (the ideal gas constant) and we need to convert the temperature to Kelvins. Assuming R = 0.0821 L·atm/(mol·K), and converting the temperature to Kelvins (294.15 K), we can calculate the partial pressure of the third gas.

P = nRT/V

P = (0.130 mol)(0.0821 L·atm/(mol·K))(294.15 K) / (8.25 L) = 0.389 atm (approx.)

We can now sum the partial pressures to find the total pressure.

Ptot = 0.323 atm + 0.660 atm + 0.389 atm = 1.372 atm

The total pressure in the container after adding the third gas at the same volume and temperature is approximately 1.372 atm.