Final answer:
The 1.50 V battery would move a total charge of 188.24 Coulombs for a 12.7 minute operation, which corresponds to approximately 1.18 * 10^21 electrons.
Step-by-step explanation:
The question refers to examining the electrical charge transferred and the number of electrons involved during the operation of a flashlight powered by a 1.50 V battery for a specific period. The power provided by the battery and the operational time of the flashlight is given.
(a) To find the total charge moved, we use the formula: Q = P * t / V. The power (P) is 0.373 watts, the time (t) is 12.7 minutes, which should be converted to seconds (760.2 s), and the voltage (V) is 1.50 V. Plugging in these values, we get Q = 0.373 * 760.2 / 1.50 = 188.24 C (Coulombs).
(b) To find the number of electrons, we divide the total charge by the charge per electron which is 1.6 * 10^-19 C. Hence, Number of electrons = Q / charge per electron = 188.24 / (1.6 * 10^-19) which comes out to be approximately 1.18 * 10^21 electrons.
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