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Give the equation of the parabola with vertex(3,-1) through the point (5,9)

User PhiLho
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1 Answer

5 votes

Answer:

y = 2.5x² - 15x + 21.5

Explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

here (h, k ) = (3, - 1 ) , then

y = a(x - 3)² - 1

to find a substitute the point (5, 9 ) into the equation

9 = a(5 - 3)² - 1 ( add 1 to both sides )

10 = a(2)² = 4a ( divide both sides by 4 )


(10)/(4) = a , then

a = 2.5

the equation of the parabola is then

y = 2.5(x - 3)² - 1 ← expand parenthesis using FOIL

= 2.5(x² - 6x + 9) - 1 ← distribute parenthesis by 2.5

= 2.5x² - 15x + 22.5 - 1

y = 2.5x² - 15x + 21.5 ← equation of parabola

User Citronas
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