Final answer:
To identify the metal M in the compound MF2, the molar mass of MF2 was calculated using the provided amount of substance (0.351 mol) forming 27.4 g of MF2. The molar mass of Fluorine was subtracted from the molar mass of MF2 to find the molar mass of the metal M, which closely matches that of calcium (Ca).
Step-by-step explanation:
To identify the metal M from the compound MF2, we start by calculating the molar mass of MF2. We have 0.351 mol of the metal, and this amount of substance forms 27.4 g of MF2. From the molecular formula MF2, we know there is 1 atom of M in each formula unit, thus 0.351 mol of M will be present in 0.351 mol of MF2.
First, we calculate the molar mass of MF2:
Molar mass of MF2 = Mass of sample / Number of moles
= 27.4 g / 0.351 mol = 78.06 g/mol (approximately).
We know the molar mass of F (Fluorine) is about 19 g/mol, so for two fluorine atoms, the combined mass would be around 38 g/mol. Subtracting this from the molar mass of MF2 gives us the molar mass of the metal M:
Molar mass of M = Molar mass of MF2 - Mass of 2 F
= 78.06 g/mol - 38 g/mol = 40.06 g/mol (approximately).
Examining the options provided, magnesium (Mg) has an atomic mass close to 24.31 g/mol, which isn't a match. Calcium (Ca), with an atomic mass of about 40.08 g/mol, is a close match. The other options, such as strontium (Sr), argon (Ar), and potassium (K), do not match the calculated molar mass.
Therefore, the metal M in the compound MF2 is most likely calcium (Ca).