Question

Propose the structure of a compound that exhibits the following ¹H NMR data. C₅H₁₂o

- 0.91 ppm (3H, triplet) - 1.19ppm(6H, singlet) - 1.50ppm(2H, quartet) - 2.24ppm(1H, singlet) Propose the structure of a compound that exhibits the following ¹H NMR data. C₄H₁₀ O - 0.90ppm(6H, doublet) - 1.76ppm(1H, multiplet) - 3.38ppm(2H, doublet) - 3.92ppm(1H, singlet)

Answer 1

The compound with the given ¹H NMR data can be proposed as 2-methylbutanol.

Step-by-step explanation:

The compound with the given ¹H NMR data (C₅H₁₂O) can be proposed as 2-methylbutanol. Here's how the structure corresponds to the given data:

• 0.91 ppm (3H, triplet) - The chemical shift of 0.91 ppm corresponds to the methyl group (-CH₃).
• 1.19 ppm (6H, singlet) - The chemical shift of 1.19 ppm corresponds to the six methyl groups (-CH₃).
• 1.50 ppm (2H, quartet) - The chemical shift of 1.50 ppm corresponds to the two methylene groups (-CH₂-).
• 2.24 ppm (1H, singlet) - The chemical shift of 2.24 ppm corresponds to the hydrogen attached to the oxygen atom (-OH).