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You toss a ball straight up by giving it an initial upward velocity of 18 m/s. What is the velocity of the ball 0.50 s after you released it

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Sure, in this case, we are going to use the equation of motion, which is: final_velocity = initial_velocity - g * time

Given:
- Initial velocity of the ball (u) = 18 m/s
- Time (t) = 0.50 seconds
- Acceleration due to gravity (g) = 9.8 m/s²

Let's find the final velocity (v) of the ball after 0.50 seconds.

Firstly, we need to multiply the acceleration due to gravity (g) with the time (t).
This means we need to multiply 0.50 seconds by 9.8 m/s², which results in 4.9 m/s.

Next, from the initial velocity (u), which is 18 m/s, we need to subtract the result of the multiplication (4.9 m/s) to get the final velocity.
So, 18 m/s minus 4.9 m/s will give us the final velocity (v) of the ball after 0.50 seconds.

Thus, the final velocity (v) of the ball after 0.50 second would be 13.1 m/s.

Please be aware of the negative sign in the equation. It indicates that the final velocity is in the opposite direction to the direction of the initial velocity because the ball is moving upward against the force of gravity.

User Chris Visser
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