Question

A bee flies at 6 feet per second directly to a flowerbed from its hive the bee stays at the flowerbed for 17 minutes, and then flies directly back to the hive at 4 feet per second. It is away from the hive for a total of 20 minutes.

a. What equation can you use to find the distance of the flowerbed from the​ hive?
b. How far is the flowerbed from the​ hive?

Answer 1

Answer:For the first part of the bee's journey, from the hive to the flowerbed, we can use the equation: distance = rate × time. The rate is 6 feet per second and the time is the unknown variable. Let's call it "t1". So the equation becomes: distance = 6t1.

For the second part of the bee's journey, from the flowerbed back to the hive, we can use the same equation: distance = rate × time. The rate is 4 feet per second and the time is also unknown. Let's call it "t2". So the equation becomes: distance = 4t2.

Now, we know that the bee is away from the hive for a total of 20 minutes. This means the sum of the times for the two parts of the journey is 20 minutes. So we can write the equation: t1 + t2 = 20.

These are the equations we can use to find the values of t1 and t2 and solve the problem.

Explanation: