Answer:
B. 104.48
Explanation:
You want the measure of angle A in triangle ABC with sides a=16, b=12, c=8.
Law of Cosines
The law of cosines lets us find angle A from ...
a² = b² +c² -2bc·cos(A)
Solving for A gives ...
A = arccos((b² +c² -a²)/(2bc)) = arccos((12² +8² -16²)/(2·12·8))
A = arccos(-1/4) ≈ 104.48°
Angle A is about 104.48°, choice B.
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