How many atoms are there in a 15.4g Iron?

Question

asked Mar 26, 2024 214k views

1 Answer

Jekis · Answer 1 · 2024-03-30T19:17:40+0000

Answer:

$1.66*10^(23)\hspace{4}atoms$

Step-by-step explanation:

We're given:

First, determine moles (n):

n=(m)/(M) where m is mass and M is molar mass

n=(15.4)/(55.85) (molar mass taken from a periodic table)

$n=0.27573858549\hspace{4}mol$

Now, multiply the moles by Avogadro's number to find atoms:

$0.27573858549*6.02*10^(23)\\= 1.6599463*10^(23)$

Round to 3 significant figures:

$1.66*10^(23)\hspace{4}atoms$