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How many atoms are there in a 15.4g Iron?

1 Answer

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Answer:


1.66*10^(23)\hspace{4}atoms

Step-by-step explanation:

Avogadro's Number

We're given:

  • Fe
  • m = 15.4 g

First, determine moles (n):


n=(m)/(M) where m is mass and M is molar mass


n=(15.4)/(55.85) (molar mass taken from a periodic table)


n=0.27573858549\hspace{4}mol

Now, multiply the moles by Avogadro's number to find atoms:


0.27573858549*6.02*10^(23)\\= 1.6599463*10^(23)

Round to 3 significant figures:


1.66*10^(23)\hspace{4}atoms

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