Answer:
-x + 6.
Explanation:
To find the equation of the line that passes through the points Q(2, 4) and R(-3, 9), you can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Where (x1, y1) is a point on the line, m is the slope of the line.
First, calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Given Q(2, 4) and R(-3, 9):
m = (9 - 4) / (-3 - 2) = 5 / -5 = -1
Now that you have the slope, choose one of the points (let's use Q: x1 = 2, y1 = 4) and plug it into the point-slope form:
y - 4 = -1(x - 2)
Simplify the equation:
y - 4 = -x + 2
Add 4 to both sides:
y = -x + 6
So, the equation of the line passing through Q(2, 4) and R(-3, 9) is y = -x + 6.