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JK with endpoints J(1,-4) and K(9,3)

User TBBle
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1 Answer

6 votes

Answer:

(7/8)x - 39/8.

Explanation:

To find the equation of the line that passes through the points J(1, -4) and K(9, 3), you can follow the same steps as before:

1. Calculate the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Given J(1, -4) and K(9, 3):

m = (3 - (-4)) / (9 - 1) = 7 / 8

2. Use one of the points (let's use J: x1 = 1, y1 = -4) and plug it into the point-slope form:

y - (-4) = (7/8)(x - 1)

Simplify the equation:

y + 4 = (7/8)x - 7/8

3. Subtract 4 from both sides:

y = (7/8)x - 7/8 - 4

y = (7/8)x - 7/8 - 32/8

y = (7/8)x - 39/8

So, the equation of the line passing through J(1, -4) and K(9, 3) is y = (7/8)x - 39/8.

User Kjhughes
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