Question

Imagine your derive the following expression by analyzing the physics of a particular system v2=v20 +2ax. The problem requires solving for x, and they known values for the system are a=2.55 meter/second2, v0 = 21.8 meter/second, and v=0 meter/second. Perform the next in the analysis

Answer 1

To solve for x in the given expression v^2 = v0^2 + 2ax, we can substitute the known values into the equation and solve for x.

Given:

a = 2.55 m/s^2 (acceleration)

v0 = 21.8 m/s (initial velocity)

v = 0 m/s (final velocity)

Substituting these values into the equation, we have:

(0)^2 = (21.8)^2 + 2(2.55)x

Simplifying further:

0 = 475.24 + 5.1x

To isolate x, we need to move the constant term to the other side of the equation:

-475.24 = 5.1x

Now, divide both sides of the equation by 5.1:

x = -475.24 / 5.1

Calculating the value:

x ≈ -93.33 meters

Therefore, based on the given values, solving the equation results in x ≈ -93.33 meters.