Question

(9%) Problem 2: Consider a 470 nm wavelength blue light falling on a pair of slits separated by 0.065 mm. At what angle (in degrees) is the first-order maximum for the blue light? 0 =

Answer 1

To find the angle at which the first-order maximum occurs for blue light with a wavelength of 470 nm, we can use the formula for the angle of diffraction:

θ = λ / d

Where θ is the angle of diffraction, λ is the wavelength of the light, and d is the separation between the slits.

Given that the wavelength of the blue light is 470 nm (or 4.7 x 10^-7 m) and the separation between the slits is 0.065 mm (or 6.5 x 10^-5 m), we can substitute these values into the formula:

θ = (4.7 x 10^-7 m) / (6.5 x 10^-5 m)

Simplifying the equation, we get:

θ = 0.00723

To convert this angle to degrees, we multiply by 180/π:

θ (in degrees) = (0.00723) x (180/π)

Using a calculator, we find that the angle at which the first-order maximum occurs for the blue light is approximately 0.415 degrees.

Explanation: