Question

Question

What is the distance of segment AB with endpoints A(-1, -2) and B(6, 12)?
A. √245
B. √125
C. √147

Answer 1

AB = √((-1 - 6)² + (-2 - 12)²)

= √((-7)² + (-14)²)

= √(49 + 196)

= √245

The correct answer is A.

Answer 2

A

Explanation:

calculate the distance d using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

with (x₁, y₁ ) = A (- 1, - 2 ) and (x₂, y₂ ) = B (6, 12 )

substitute these values into the formula for d

d =
`√((6-(-1))^2+(12-(-2))^2)`

=
`√((6+1)^2+(12+2)^2)`

=
`√(7^2+14^2)`

=
`√(49+196)`

=
`√(245)`