Question

Find the value of s in the equation:
16-s^2=30

Answer 1

Answer:
`s=√(14)i, s=-√(14)i` (where i is *outside* of the radical)

Explanation:

`16-s^2=30\\-s^2=30-16\\-s^2=14\\`

Now divide both sides of the equation by negative one (-1):

`s^2=-14`

Take the square root of both sides to get rid of the exponent on the variable:

`√(s^2)=√(-14) \\s=√(-14) , s=-√(-14)`

Then because the square root of -1 can be written as imaginary number "I",

`√(-14)` becomes
`√(14)i`, and
`-√(-14)` becomes
`-√(14)i`.

So,
`s=√(14)i, s=-√(14)i`