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23 votes
23 votes
Construct a frequency polygon that represents the following data regarding the selling prices of houses sold in 2006 for a particular neighborhood find the midpoint

Class Frequency
78787 – 98786 9
98787 – 118786 8
18787 – 138786 9
138787 – 158786 4
158787 – 178786 8

User Marcin Olichwirowicz
by
2.2k points

1 Answer

9 votes
9 votes

Answer:

See attachment for polygon

Explanation:

Given


\begin{array}{cc}{Class} & {Frequency} & 78787 - 98786 & 9 &98787 - 118786 & 8 & 118787 - 138786 & 9 & 138787 - 158786 & 4 & 158787 - 178786 & 8 \ \end{array}

Required

The frequency polygon

First, we calculate the midpoint of each class.

This is the average of the class limits

So, we have:


x_1 = (78787 + 98786)/(2) = (177573)/(2) = 88786.5


x_2 = (98787 + 118786)/(2) = (217573)/(2) = 108786.5

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x_5 = (158787 + 178786)/(2) = (337573)/(2) = 168786.5

(138787 + 158786)/2

So, the table becomes:


\begin{array}{ccc}{Class} & {Frequency} & {x} &78787 - 98786 & 9 & 88786.5 & 98787 - 118786 & 8 & 108786.5 & 118787 - 138786 & 9 & 128786.5 & 138787 - 158786 & 4 & 148787.5 & 158787 - 178786 & 8 & 168786.5\ \end{array}

See attachment for frequency polygon

Construct a frequency polygon that represents the following data regarding the selling-example-1
User Ritesh Gune
by
3.3k points