Answer:
to heat a 3.5 kg gold bar from 21°C to 67°C is approximately 21387 Joules.
Step-by-step explanation:
To calculate the heat required to heat a substance, you can use the formula:
Q = m * c * ΔT
Where:
Q = Heat energy (in Joules)
m = Mass of the substance (in kilograms)
c = Specific heat capacity of the substance (in J/kg°C)
ΔT = Change in temperature (in °C)
For gold, the specific heat capacity (c) is approximately 129 J/kg°C.
Given:
m = 3.5 kg
c = 129 J/kg°C
ΔT = 67°C - 21°C = 46°C
Plug the values into the formula:
Q = 3.5 kg * 129 J/kg°C * 46°C
Q = 21387 J
So, the amount of heat required to heat a 3.5 kg gold bar from 21°C to 67°C is approximately 21387 Joules.