Question

A tortoise crawling at a rate of 0.1 mph passes a resting hare. The hare wants to rest another 30 minutes before chasing the tortoise at a rate of 5 mph. How many feet must the hare run to catch the tortoise?

Answer 1

Hello!

Lets solve!

The speed of the tortoise is 0.1 mi/hr

The speed of the hare is 5mi/hr.

The tortoise runs 0.1 miles in 1 hour

The tortoise will run x miles in 0.5 hours.

x = 0.5 X 0.1

= 0.05 miles.

Therefore, the distance covered by the Tortoise within 30 minutes is 0.05 miles.

The hare will have to run for 0.05 miles before he can catch up to the tortoise.

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The hare will have to run 264 feet to catch up with the hare!

Hope this helps! o(〃＾▽＾〃)o