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19 votes
19 votes
Find(g-f)(x)

f(x)=1/x
g(x)=x^2+2x-5

a. 1/x-x^2-2x+5
b.1/x+x^2+2x-5
c.x^2+2x-5-1/x
d.1/x+x^2-5

Find(g-f)(x) f(x)=1/x g(x)=x^2+2x-5 a. 1/x-x^2-2x+5 b.1/x+x^2+2x-5 c.x^2+2x-5-1/x-example-1
User Dmachop
by
3.6k points

2 Answers

17 votes
17 votes

Answer:

c. x² + 2x - 5 - 1 / x

Explanation:

f ( x) = 1 / x.

g ( x) = x² + 2x - 5

so,

( g - f) ( x) = x² + 2x - 5 - 1 / x

User Jimmy Chandra
by
3.1k points
10 votes
10 votes

Answer:

x^2+2x-5 - 1/x

Explanation:

f(x)=1/x

g(x)=x^2+2x-5

(g-f)(x) = x^2+2x-5 - 1/x

User TheMethod
by
3.2k points