Question

object 1: x(t)=a , where a = 5 m object 2: x(t)=bt+c , where b = +4 m/s and c = -1 m object 3: x(t)=et2+ft , where e = +5 m/s2 and f = -9 m/s object 4: x(t)=gt2+h , where g = -4 m/s2 and h = +16 m .What is the earliest time when object 4 is at the origin? Time t can be negative.

Answer 1

T is equal to -2

To find when object 4 is at the origin (x = 0), you need to solve the equation x(t) = gt^2 + h = 0. For object 4, g = -4 m/s^2 and h = 16 m. Plugging in these values:

-4t^2 + 16 = 0

Solving for t:

t^2 = 16 / 4
t^2 = 4
t = ±2

So, the earliest time when object 4 is at the origin is t = -2.