Answer:
V = 5.38 m/S
Step-by-step explanation:
Given that,
A tennis ball is dropped from 1.48 m
above the ground, d = 1.48 m
It rebounds to a height of 0.956 m
We need to find the velocity of the ball when it hits the ground. Using equation of kinematics as follows :
42-42 = 2ad
03 = 2ad + 43
ぃ = V2ad + 12
v = v2 x 9.8 × 1.48 + (0)2
v = 5.38 m/s
So, when the ball hits the ground, its velocity is 5.38 m/s.