Answer:
(-4/3, 2]
Explanation:
f(x)= sqrt (4-x^2)
g(x) = sqrt (3x+4)
domain of f(x)/ g(x)
The domain of the numerator is
4-x^2 ≥ 0
4 ≥x^2
Taking the square root of each side
-2 ≤x≤2
The domain of the denominator
3x+4 > 0 ( the denominator cannot be zero)
3x>-4
x > -4/3
Combine the restrictions to make it most restrictive
-4/3<x≤2
In interval notation
(-4/3, 2]