Question

Solve this for points

Answer 1

78cm²

Given :

• Height = 6cm
• b¹ = 16cm
• b² = 10cm

To find :

• Area

Solution:

We know that,

• Area of a trapezoid = 1/2(b¹ + b²)h

where,

• b¹ = 16cm
• b² = 10cm
• h = 6cm

Plugging in the values,

• Area of the given trapezoid = 1/2 (16cm +10cm)6cm
• Area of the given trapezoid = 3 x 26cm²
• Area of the given trapezoid = 78cm²

Therefore,the area of the given trapezoid would be equal to 78cm².

Answer 2

78 cm²

Explanation:

The formula for the area of a trapezoid is:

`\large\boxed{A=(1)/(2)h(b_1+b_2)}`

where:

• h is the height.
• b₁ and b₂ are the parallel bases.

Given values:

• h = 6 cm
• b₁ = 16 cm
• b₂ = 10 cm

To calculate the area of a trapezoid with the given parameters, we can substitute the values of h, b₁ and b₂ into the area formula and solve for A:

`\begin{aligned}A&=(1)/(2)h(b_1+b_2)\\\\\implies A&=(1)/(2) \cdot 6 (16+10)\\\\A&=(1)/(2) \cdot 6 \cdot26\\\\A&=3 \cdot 26\\\\A&=78\; \sf cm^2\end{aligned}`

Therefore, the area of a trapezoid in which the height is 6 cm and the two bases are b₁ = 16 cm and b₂ = 10 cm is:

`\Large\boxed{\boxed{78\;\sf cm^2}}`