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Write the equation of a circle that has a diameter of 16 units and its center is at (3, -5). **type in question**

User Adam Pope
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Answer:

(x - 3)² + (y + 5)² = 64

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given diameter = 16 , then r = 16 ÷ 2 = 8

with centre = (3, - 5 ) , then equation of circle is

(x - 3)² + (y - (- 5) )² = 8² , that is

(x - 3)² + (y + 5)² = 64

User Aquiles
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