Question

Line AB passes through A(-3, 0) and B(-6, 5) What is the equation of the line that passes through the origin and is parallel to line AB?

О A. 5x - 3у= 0
• в. -x + 3= 0
O c. 5x - 3=0
• D. 3x + 5 = 0
O E. -3x + 5 = 0

Answer 1

Hi,

Answer A with a mistake

Explanation:

`slope\ of\ AB=(5-0)/(-6-(-3)) =-(5)/(3) \\Equation\ of\ the\ parallel\ passing\ through\ the\ origin:\\y-0=(x-0)*(-(5)/(3) )\\3y=-5x\\\\\boxed{5x+3y=0}\\`