Question

In a 4*2 design with 80 participants distributed equally across the conditions, what are kA*B and nA1B1?

A. kA*B = 4; nA1B1 =20
B. kA*B=6; nA1B1=10
C. kA*B=8; nA1B1=10
D. kA*B=8; nA1B1= 80

Answer 1

According to the details given in the problem, the experiment has a 4*2 design. This means that there are 4 levels of factor A and 2 levels of factor B.

First, we'll calculate kA*B which represents the total number of conditions in the experiment. To do that, we multiply the number of levels of factor A and B together. So, 4*2 equals 8. Hence, kA*B equals 8.

Secondly, we determine nA1B1 which stands for the number of participants in one condition (level 1 of A and level 1 of B). Since the total number of participants is 80 and they are evenly distributed across all conditions, we simply divide the total number of participants by the number of conditions. 80 divided by 8 (the value of kA*B) equals 10.

So in conclusion, for this experimental design, kA*B equals to 8 and nA1B1 equals to 10. That corresponds to option C in the provided choices.