For problem 5, the sample data is [20, 13, 4, 8, 10]. The variance for this can be calculated using formula σ² = Σ (Xi - μ)²/n-1 where Xi represents each score, μ is the mean of the scores, and n is the number of scores. For this data, the variance is 36.0 and the standard deviation (the square root of variance) is 6.0.
In problem 6, the sample data is [83, 65, 91, 87, 84]. Again, using the variance formula, we find the variance to be 100.0 and the standard deviation to be 10.0.
In problem 7, the population data is [3, 6, 10, 12, 14]. The process is the same as before, but when calculating variance for a population, we use n instead of n-1. In this case, the variance is 20.0 and the standard deviation is approximately 4.47.
In problem 8, for the data set [1, 19, 25, 15, 12, 16, 28, 13, 6], the variance is 72.0 and the standard deviation is approximately 8.49.
In problem 9, with the sample data as [6, 52, 13, 49, 35, 25, 31, 29, 31, 29], the variance comes to be 196.0 and the standard deviation is 14.0.
In problem 10, for population data [4, 10, 12, 12, 13, 21], the variance is 30.0 and the standard deviation is approximately 5.48.
Given the miles per gallon for a 2013 Ford Fusion in problem 11 with data [34.0, 33.2, 37.0, 29.4, 23.6, 25.9], the variance is approximately 26.35 and the standard deviation is approximately 5.13.
In problem 12, the sample timing data for the exam [60.5, 128.0, 84.6, 122.3, 78.9, 94.7, 85.9, 89.9] yields a variance of approximately 495.99 and a standard deviation of approximately 22.27.
For problem 13, the strength measures of concrete mix [3960, 4090, 3200, 3100, 2940, 3830, 4090, 4040, 3780] give a variance of 211275.0 and a standard deviation of approximately 459.65.
Finally, for the flight times in problem 14 with data [282, 270, 260, 266, 257, 260, 267], the variance is 71.0 and the standard deviation is approximately 8.43.