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Add and simplify. You may leave the denominator in fac (-2x-10)/(x^(2)+7x+10)+(10)/(x+2)

User Tttppp
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1 Answer

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To simplify this mathematical expression, we first need to understand the structure of the expressions that we're given.

We have two fractions:

Expression 1: (-2x - 10) / (x^2 + 7x + 10)
Expression 2: 10 / (x + 2)

We're being asked to add these two fractions and simplify the result. Now, in order to add fractions, we must have a common denominator.

Looking at the denominators, you can see that the denominator in Expression 1 (x^2 + 7x + 10) is a quadratic expression that can be factored into two binomials.

Let's do that:

x^2 + 7x + 10 = (x + 2)(x + 5)

Now Expression 1 becomes: (-2x - 10) / [(x + 2)(x + 5)]

Comparing the denominators of the two expressions, we observe that the denominator (x+2) is common to both fractions.

Now, let's rewrite our problem:

(-2x - 10) / [(x + 2)(x + 5)] + 10 / (x + 2)

With the common denominator of (x + 2), we can add these two fractions:

{(-2x - 10) + 10*(x + 5)} / [(x + 2)(x + 5)]

Simplify the numerator:

(-2x - 10 + 10x + 50) / [(x + 2)(x + 5)]

Further simplification gives:

(8x + 40) / [(x + 2)(x + 5)]

The last step to simplifying fractions is to cancel all common factors from the numerator and the denominator.

We see that the number 8 is a common factor, let's divide both numerator and denominator by 8:

x + 5 / [(x + 2)(x + 5/8)]

After simplifying, the (x + 5) factor cancels out:

8 / (x + 2)

Hence, the simplified form of the given expression is 8 / (x + 2).

User Nijat Aliyev
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