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Consider the circle (x+1)^(2)+(y-4)^(2)=64. a Find the distance from the point (-1,-3) to the centre of the circle.

User Raigex
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To find the distance from a point to the center of a circle, we first need to identify the center of the circle. The standard equation of a circle is (x-h)²+(y-k)²=r², where (h, k) is the center of the circle and r is the radius. Given our equation (x+1)²+(y-4)²=64, we can immediately identify the center of our circle as (-1, 4).

The distance between two points in a plane can be calculated using the Distance Formula, which is derived from the Pythagorean Theorem. The distance d between two points (x1, y1) and (x2, y2) is given by:

d = √[(x2 - x1)² + (y2 - y1)²]

Our two points in this case are the center of the circle (-1, 4), and the given point (-1, -3).

Substituting (-1, 4) into (x1, y1) and (-1, -3) into (x2, y2) and applying these values in the Distance Formula, we get:

d = √[(-1--1)² + (-3-4)²]
= √[(0)² + (-7)²]
= √[0 + 49]
= √49
= 7

So, the distance from the point (-1,-3) to the center of the circle is 7 units.

User Elsie
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