76.9k views
0 votes
Danielle has a bag with marbles: 5 red, 8 rellow, 3 blue, and 1 green. One marble is andomly picked out of the bag. What is he probability she picks a marble that is ed or blue?

User Annelaure
by
8.1k points

1 Answer

3 votes

Let's first determine the total number of marbles Danielle has in her bag. She has 5 red marbles, 8 yellow marbles, 3 blue marbles, and 1 green marble. So in total, she has 5 + 8 + 3 + 1 = 17 marbles.

Now, let's figure out the number of marbles that meet Danielle's criteria of being either red or blue. She has 5 red marbles and 3 blue marbles, which together make 5 + 3 = 8 marbles.

The probability of an event is calculated as the ratio of the favorable outcomes to the total possible outcomes.

Here, the favorable outcome is picking a red or a blue marble, and the total possible outcomes is the total number of all marbles in the bag.

Therefore, the probability of picking a red or blue marble is 8 (red and blue marbles) divided by 17 (total marbles).

As a result, the probability is around 0.47058823529411764 when calculated in a decimal format. If you prefer to leave your answer as a fraction, this would roughly be equivalent to 8/17.

So, Danielle has a 8 in 17 or approximately a 0.47 chance (rounded to two decimal places) to draw a either a red or blue marble from the bag.

User Willian Adamczyk
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories