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3 The quadratic equation x^(2)-6x=12 is rewritten in the form (x+p)^(2)=q, where q is a constant. What is the value of p ? -12 -9 -3 9

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To solve for p, we have to put the equation in the specific format that is required, which is (x+p)^2 = q.

For this equation, we start off with the equation given, which is x^2 - 6x = 12.

The equation x^2 - 6x = 12 can be rewritten in the form (x+p)^2 = q, which is obtained by completing the square.

Completing the square involves taking the coefficient of the x term (which is -6), dividing it by 2, and then squaring it. Applied to our problem, the coefficient -6 divided by 2 equals -3, and squaring -3 gives us the 9.

So, by adding 9 in both side of the equation which doing to keep the equation balance, we get the following equation: x^2 - 6x + 9 = 12 + 9.

This can be rewritten as (x-3)^2 = 21. So in comparison with the format ((x+p)^2 = q), it's clear that p equals -3.

Therefore, the value of p, given the equation can be rewritten as (x+p)^2 = q, is -3.

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