Question

Solve for n. 10n^(2)+49n-5=0 Write each solution as an ini

Answer 1

Answers: n = 1/10 and n = -5

Work Shown

There are a few approaches we could do, but I'll use the quadratic formula.

a = 10

b = 49

c = -5

`n = (-b\pm√(b^2-4ac))/(2a)\\\\n = (-49\pm√((49)^2-4(10)(-5)))/(2(10))\\\\n = (-49\pm√(2401+200))/(2(10))\\\\n = (-49\pm√(2601))/(20)\\\\n = (-49\pm51)/(20)\\\\n = (-49+51)/(20) \ \text{ or } \ n = (-49-51)/(20)\\\\n = (2)/(20) \ \text{ or } \ n = (-100)/(20)\\\\n = (1)/(10) \ \text{ or } \ n = -5\\\\`

Note: 1/10 = 0.1 exactly