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A bag has 5 yellow marbles, 3 red marbles, and 2 blue marbles. Quinn randomly picks a marble from the bag and returns it before another is picked. How many times would Quinn expect to pick a blue marb

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Sure, let's find the answer step by step.

1. First, we calculate the total number of marbles in the bag. That's simply the sum of the yellow, red, and blue marbles. So we add 5 yellow marbles, 3 red marbles, and 2 blue marbles to get a total of 10 marbles.

2. Next, we calculate the probability of Quinn picking a blue marble. Probability is defined as the desirable outcomes divided by all possible outcomes. In this case, we want Quinn to draw a blue marble, so the favorable outcome is the number of blue marbles, which is 2. The total possible outcome is the total number of marbles, which is 10. So the probability of drawing a blue marble is 2 divided by 10, which simplifies down to 0.2.

3. Now Quinn wants to know how many times they could expect to draw a blue marble if they pick a marble 100 times. Since we know the probability of drawing a blue marble is 0.2, setting that probability to the number of times Quinn picks a marble will determine on average, how many times a blue marble will be picked.

So, Quinn expects to pick blue marble in 0.2 * 100 trials, which is equals to 20.

So, we can conclude that, on average, Quinn would expect to pick a blue marble about 20 times out of 100 trials. This answer is based on probability and the law of large numbers; the actual result may vary each time you carry out 100 trials.

User Gwalshington
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