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Y ≥ - 5/3x - 5 how do i graph this?

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Answer:

Refer to the step-by-step explanation and the attached image.

Explanation:

The main steps involved are graphing the boundary line, choosing the type of line (solid or dashed), and determining the region to shade.


\hrulefill

Graphing the Boundary Line
\hrulefill

To graph the inequality:


y \geq -(5)/(3)x-5

You'll start by graphing the line:


y = -(5)/(3)x-5

Steps on how to Graph a Line:

To graph a line in the form y = mx + b:

1. Plot 'b' on the y-axis as your starting point.

  • In our case, 'b' is the point (0, -5)

2. From there, move 'm' units up (down if -m) and 1 unit right to mark a new point.


\text{Recall that} \ m =\frac{\text{rise}}{\text{run}}

  • In our case move 5 units down (since 'm' is negative) and 3 units right

3. Connect the points with a straight line.

Optionally, you can plot more points using the slope for increased accuracy, and then draw the line through all the points.

This graphed line represents the boundry line.


\hrulefill

Determining the Type of Line:
\hrulefill

  • If < or > then dashed line.
  • If ≤ or ≥ than solid line.

In our case we have a solid line.


\hrulefill

Shading the Region
\hrulefill

1. Choose a test point that is not on the line to determine which side of the line to shade. A common choice is the origin (0,0), provided the line doesn't pass through it.

2. Substitute the coordinates of the test point into the inequality.


\Longrightarrow 0 \geq -(5)/(3)(0)-5\\\\\\\\\therefore 0 \geq -5 \ \bold{True}

3. Since the inequality holds, we shade the region that contains the test point.

Y ≥ - 5/3x - 5 how do i graph this?-example-1
User Tamba
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