Answer:
To find the final velocity of the bus after 9.0 seconds, we can use the equation:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
u = 16.5 m/s (initial velocity)
a = 2.75 m/s^2 (acceleration)
t = 9.0 s (time)
Plug in the values into the equation:
v = 16.5 + (2.75)(9.0)
v = 16.5 + 24.75
v = 41.25 m/s
Therefore, the final velocity of the bus after 9.0 seconds will be 41.25 m/s.