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One mole of aspartame (C14H18N2O5) reacts with two moles of water to

produce one mole of aspartic acid (C4H7NO4), one mole of methanol
(CH3OH) and one mole of phenylalanine.
a. What is the molecular formula of phenylalanine? C9H11NO2
b. What mass of phenylalanine is produced from 378 g of aspartame?

1 Answer

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Answer:

To determine the mass of phenylalanine produced from 378 g of aspartame, we need to calculate the molar mass of phenylalanine and use stoichiometry.

a. The molecular formula of phenylalanine is C9H11NO2, as you correctly stated.

b. First, let's calculate the molar mass of phenylalanine:

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of N = 14.01 g/mol

Molar mass of O = 16.00 g/mol

Molar mass of phenylalanine (C9H11NO2) = (9 * 12.01) + (11 * 1.01) + 14.01 + (2 * 16.00)

≈ 165.19 g/mol

Now, using the stoichiometry of the reaction, we know that one mole of aspartame (C14H18N2O5) produces one mole of phenylalanine (C9H11NO2).

Molar mass of aspartame (C14H18N2O5) = (14 * 12.01) + (18 * 1.01) + (2 * 14.01) + (5 * 16.00)

≈ 294.30 g/mol

Moles of aspartame = mass of aspartame / molar mass of aspartame

Moles of aspartame = 378 g / 294.30 g/mol

≈ 1.285 mol

From the stoichiometry, we know that one mole of aspartame produces one mole of phenylalanine. Therefore, the moles of phenylalanine produced will also be approximately 1.285 mol.

Now, we can calculate the mass of phenylalanine produced:

Mass of phenylalanine = moles of phenylalanine * molar mass of phenylalanine

= 1.285 mol * 165.19 g/mol

≈ 212.43 g

Therefore, approximately 212.43 g of phenylalanine is produced from 378 g of aspartame.

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