Answer:
(A' ∪ C) ∪ (A ∩ B) = {a, b, c, d, e, f, g, h, i, j, k}.
Explanation:
Note:
- A' is the complement of set A, which contains all elements in the universal set U that are not in A.
- A ∪ C is a union of sets A and C, which contains all elements that are in either A or C.
- A ∩ B is the intersection of sets A and B, which contains all elements that are in both A and B.

For the Question:
Let's find the values for each set:
- A' (complement of A): {b, e, h, j, k}
- A ∪ C (union of A and C): {a, b, c, d, f, g, i, j}
- A ∩ B (intersection of A and B): {c, d, f, g}
Now, let's proceed with the given expression:
(A' ∪ C) ∪ (A ∩ B)
Evaluate (A' ∪ C):
(A' ∪ C) = {b, e, h, j, k} ∪ {a, b, f, i, j}
(A' ∪ C) = {a, b, e, f, h, i, j, k}
Now, union this result with (A ∩ B):
{a, b, e, f, h, i, j, k} ∪ {c, d, f, g}
The resulting set will be:
{a, b, c, d, e, f, g, h, i, j, k}
So, (A' ∪ C) ∪ (A ∩ B) = {a, b, c, d, e, f, g, h, i, j, k}, which is the universal set U.