Question

A force of 15 lbs is applied to the input piston in a hydraulic jack. If the input piston area and output piston area are 1.2 in² and 2.4 in²2

respectively, what is the output force?


a.30 psi
b.38 psi
C. 134 psi
d. 7 psi

Answer 1

Step-by-step explanation:

Pressure P = Force F / Area A

Hydraulic pressure is equal at the surface of water at the input and output sides.

So P = F1 ÷ A1 = F2 ÷ A2

=> F2 = F1 × A2 ÷ A1

= 15 × 2.4 ÷ 1.2 = 30 lbs

Output force= 30 lbs.

Output pressure = 30 lbs /2.4 in² = 12.5 psi