Question

What is the value of x in the equation 6(x + 1) - 5x = 8 + 2(x - 1)?

Answer 1

Explanation:

Given equation,

`6(x + 1) - 5x = 8 + 2(x - 1)`

Opening the parentheses and expanding the equation,

`6x + 6 - 5x = 8 + 2x - 2`

Now compute the like terms both sides,

`6x - 5x + 6 = 2x + 6`

`x + 6 = 2x + 6`

Now isolate x on one side,

`x - 2x = 6 - 6`

`- x = 0 \: or \: \boxed{x = 0}`

~The value of x that satisfies the equation is 0.

Answer 2

Hello!

Answer:

`\Large \boxed{\sf x= 0}`

Explanation:

→ We want to solve this equation:

`\sf 6(x + 1) - 5x = 8 + 2(x - 1)`

◼ Simplify both sides:

`\sf 6x + 6 - 5x = 8 + 2x - 2`

`\sf x + 6 = 6+ 2x`

◼ Subtract 6 from both sides:

`\sf x + 6 -6= 6+ 2x-6`

◼ Simplify both sides:

`\sf x= 2x`

◼ Subtract 2x from both sides:

`\sf x -2x=2x-2x`

◼ Simplify both sides:

`\sf -x = 0`

◼ Divide both sides by -1:

`\sf (-x)/(-1) = (0)/(-1)`

◼ Simplify both sides:

`\boxed{\sf x= 0}`

Conclusion:

The solution of the equation 6(x + 1) - 5x = 8 + 2(x - 1) is 0.