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How do I find the focus and vertex of a parabola with the equation 24x=-(y-6)^2+192

User Luiey
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To find the focus and vertex of a parabola with the equation 24x = -(v - 6)^2 + 192, we can use the standard form of a parabola equation, which is (x - h)^2 = 4p(y - k), where (h, k) represents the vertex and p represents the distance between the vertex and the focus.

Comparing the given equation to the standard form, we can see that h = 6 and p = 48.

Sooo, the vertex of the parabola is (6, 0) and the focus is (6, 48).
User Reid Mac
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