Question

HELP ME PLS I HAVE A TEST TMRW!! Find the vertex and y intercept from the quadratic equation..

(equation is in the picture)

TOPIC: finding vertex and y intercepts from a stabsard form quadratic equation

25 points!!

Answer 1

To find the vertex and y-intercept of the quadratic equation y = -x² + 6x - 5, you can follow these steps:

1. Vertex: The vertex of a quadratic equation can be found using the formula: x = -b / (2a), where a, b, and c are the coefficients of the equation in the form ax² + bx + c. In this case, a = -1 and b = 6.

Plugging in the values, we get:

x = -6 / (2 * -1)

x = -6 / -2

x = 3

To find the y-coordinate of the vertex, substitute the x-coordinate (3) back into the equation:

y = -(3)² + 6(3) - 5

y = -9 + 18 - 5

y = 4

So, the vertex of the equation y = -x² + 6x - 5 is (3, 4).

2. Y-intercept: The y-intercept is the point where the equation intersects the y-axis. To find it, substitute x = 0 into the equation:

y = -(0)² + 6(0) - 5

y = 0 - 0 - 5

y = -5

Therefore, the y-intercept of the equation y = -x² + 6x - 5 is (0, -5).