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What is the area of triangle HIJ?

What is the area of triangle HIJ?-example-1
User Kmek
by
8.2k points

2 Answers

3 votes

Answer:

22 units²

Explanation:

HI or base = 4 units

JH or height = 11 units

Area of triangle is bh/2

4x11 = 44/2 = 22

User Andrew Jackson
by
8.0k points
3 votes

Answer:

22 sq. units.

Explanation:

To Find:

  • Area of triangle HIJ.

Solution:

Given,

Coordinates of point H (7, -4)

Coordinates of point J (-4, -4)

Coordinates of point I (7, -8)

Also, from the given diagram it can be inferred that it is a right-angled triangle.

Here,

Length of side HJ is = 7 units + 4 units = 11 units [Base]

Length of side HI is = 8 units - 4 units = 4 units [Height]

So,

By Pythagoras Theorem, length of side JI is,

=
\sqrt{11^(2) +4^(2) }

=
√(121 + 16)

=
√(137) = 11.7 (approx.) units [Hypotenuse]

Then,

Area of the triangle HIJ will be,

=
(1)/(2) × Base × Height

=
(1)/(2) × 11 units × 4 units

= 22 sq. units

Hence,

The required area of the triangle is 22 sq. units. (Ans)

User JORDANO
by
8.2k points
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