Question

What is the perimeter of triangle BCD?

Answer 1

`\text{Here, BCD is a right angled triangle with vertices B(-4, -1), C(-1, 3) and }\\\text{D(-1, -1).}\\\therefore \text{\ CD = 4 units,\ BD = 3 units}\\\\\text{Using Pythagoras theorem,}\\\\\text{BC}=\mathrm{√(CD^2+BD^2)=√(4^2+3^2)=5\ units}`

`\text{Therefore perimeter of the triangle = CD + BD + BC = 3 + 4 + 5 = 12 units}`