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Line AC and Line BD are perpendicular and intersect at point E. Ray EF bisects Angle AED. The measure of angle AEF is (4x-3) degrees, What is the value of x?

User Richelle
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1 Answer

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Answer:

12

Explanation:

Given right angle AED and its bisector EF, you want the value of x such that angle AEF is (4x -3)°.

Angle

Angle AEF is half of a 90° angle, so is 45°.

(4x -3)° = 45°

4x = 48 . . . . . . . . . divide by °, add 3

x = 12 . . . . . . . . . . . divide by 4

The value of x is 12.

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User Bennidi
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