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The answer should be accurate to at least 2 decimal places.

The answer should be accurate to at least 2 decimal places.-example-1
User Rhari
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6 votes

Answer:


\boxed{20}

Explanation:

For instantaneous rate of change, we can use differentiation and differentiate 'g' wrt 't'.

Given,


g(t) = 5 {t}^(2) - 1

According to power constant rule; d(ax^n)/dx = n*ax^(n-1). And differentiation of a constant is 0.

Differentiating 'g' wrt 't'


(d \: g(t))/(dt) = 10t

Instantaneous rate of change at t = 2,


(d \: g(2))/(dt) = 10(2) = 20

The instantaneous rate of change of g (5t² - 1) is 20.

User Ayo K
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